When light rays are incident on a prism at an angle of $45^{\circ}$ , the minimum deviation is obtained. If the refractive index of the material of prism is $\sqrt{2}$ then the angle of the prism will be

30°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60°

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
60°

Suggest Corrections

Similar questions

When light rays are incident on a prism at an angle of $45^{\circ}$ , the minimum deviation is obtained. If the refractive index of the material of prism is $\sqrt{2}$ then the angle of the prism will be

Q. The angle of incidence for a ray of light at a refracting surface of a prism is

45^{o}

. The angle of prism is

60^{o}

. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are

Q. The light ray is incident at an angle of

60^{\circ}

on a prism of angle

45^{\circ}

. When the light ray falls on the other surface at

90^{\circ}

, the refractive index of the material of prism

μ

and the angle of deviation

δ

are given by

Join BYJU'S Learning Program

When light rays are incident on a prism at an angle of 45∘, the minimum deviation is obtained. If the refractive index of the material of prism is √2 then the angle of the prism will be

The correct option is D 60°

When light rays are incident on a prism at an angle of $45^{\circ}$ , the minimum deviation is obtained. If the refractive index of the material of prism is $\sqrt{2}$ then the angle of the prism will be

The correct option is D
60°