When light rays are incident on a prism at an angle of 45∘, the minimum deviation is obtained. If refractive index of the material of prism is √2 then the angle of prism will be
A
30∘
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B
40∘
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C
50∘
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D
60∘
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Solution
The correct option is D60∘ μ=sinisinA2⇒√2=sin45sinA2⇒sinA2=1√2√2=12⇒A2=30∘⇒A=60∘