Question

When linear momentum of a body becomes n times, its kinetic energy becomes

• A. $n^2$ time
• B. $(n^2+1)$ times
• C. $\frac{1}{n^2}$ times
• D. $(n^2+2)$ times

Answer 1

The correct option is A $n^2$ time

Since $K.E.=\frac{p^2}{2m}$

where p = linear momentum

m = mass

When momentum will become n times

$K.E{.}^{\prime }=\frac{{n^{2}p}^2}{2m}$

$K.E{.}^{\prime }=n^{2}K.E.$