When liquid water is cooled, it contracts until a temperature of approximately :

4^{\circ}

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- 4^{\circ}

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10^{\circ}

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- 10^{\circ}

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Solution

The correct option is A $4^{\circ}$ C
When liquid water is cooled, it contracts until a temperature of approximately 4 $^{o} C$ . As temperature is lowered further, the volume expansion occurs.
Note: The density of water is maximum at 4 $^{o} C$ .

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Similar questions

4^{\circ}

0^{\circ}

When water cools, first it expands in volume but below 4°C it starts contracting until it reaches 0°C.

Water is cooled from $4^{\circ} C t o 0^{\circ} C$ . It :

(a) contracts (b) expands

(d) first expands, then contracts.

1 cm

25^{\circ} C

0^{\circ} C

(α = 10^{- 5} /^{\circ} C, Y = 2 \times 10^{11} {Nm}^{- 2})

1 cm

25^{\circ} C

0^{\circ} C

(α = (10^{- 5})^{\circ} C^{- 1}, Y = 2 \times 10^{11} {Nm}^{- 2})

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