Question

When Maniklal sold a car for Rs 3,45,600 he made a profit of 8%. For how much had he bought the car?

Answer 1

Let the cost price of the car = C.P = Rs x
Selling price of the car = S.P = Rs 3,45,600
Profit % = 8%
Profit = S.P - C.P
= Rs (345600 – x)
Profit % = $\frac{\mathrm{Profit}}{\mathrm{C}.\mathrm{P}}\times 100$

$$\begin{gathered} \Rightarrow 8=\frac{345600-x}{x}\times 100 \\ \Rightarrow 8x=\left(345600-x\right)\times 100 \\ \Rightarrow 8x=34560000-100x \\ \Rightarrow 8x+100x=34560000 \\ \Rightarrow 108x=34560000 \\ \Rightarrow 108x=34560000 \\ \Rightarrow x=\frac{34560000}{108} \\ \Rightarrow x=320000 \end{gathered}$$

∴ Cost price of the car is Rs 3,20,000.