When mercuric iodide is added to aqueous KI solution:

Freezing point is raised

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Osmotic pressure is raised

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Boiling point is elevated

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Vapour pressure is raised

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Solution

The correct option is A Freezing point is raised
When HgI2 is added to KI, a complex is formed.
$H g I_{2} + 2 K I \to K_{2} [H g I_{4}]$
As the number of $I^{-}$ particles decreases so freezing point increases.
Hence option A is correct.

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H g I_{2}

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[H g I_{4}]^{2 -}

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