When mercury is reacted with hot and conc. sulphuric acid, the gas evolved is:

H_{2} S

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S O_{2}

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S O_{3}

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O_{2}

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Solution

The correct option is B $S O_{2}$
$2 H g + 2 H_{2} {S O}_{4} (c o n c .) ⟶ H g_{2} {S O}_{4} + {S O}_{2} + 2 H_{2} O$
Thus it forms ${S O}_{2}$ as a gas.

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