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Standard XII

Chemistry

Reducing Nature (Group 2)

When metal 'M...

Question

When metal 'M' is treated with $N a O H$ , a white gelatinous precipitate 'X' is obtained, which is soluble in excess of $N a O H$ . Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. then metal 'M' is:

A l

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F e

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Z n

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C a

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Solution

The correct option is D $A l$
$A l + N a O H \to A l (O H)_{3} (w h i t e p p t)$

$A l (O H)_{3} + O H^{-} \to [A l (O H)_{4}]^{-} s o l u b l e$

$A l (O H)_{3} h e a t - - \to A l_{2} O_{3} + 3 H_{2} O$

Al2O3 used as adsorbent in column chromatography.

Therefore option A is correct

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Similar questions

Q. When a metal 'M' is treated with

N a O H

, a gelatinous precipitate 'X' is obtained, which is soluble in excess of

N a O H

. The compound 'X' when heated strongly, gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is:

Q. When a metal 'M' is treated with

N a O H

, a gelatinous precipitate 'X' is obtained, which is soluble in excess of

N a O H

. The compound 'X' when heated strongly, gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is:

Q. When metal

X

is treated with sodium hydroxide, a white precipitate

(A)

is obtained, which is soluble in excess of

N a O H

to give soluble complex

(B)

Compound

(A)

is soluble in dilute

H C l

to form compound

(C)

. The compound

(A)

when heated strongly gives

(D)

, which is used to extract metal.

Identify

(X), (A), (B), (C)

and

(D)

. Write suitable equations to support their identities:

Q. When metal

X

is treated with sodium hydroxide, a white ppt. of

A

is obtained which is soluble in excess of

N a O H

to form soluble complex

B

. Compound

A

is soluble in dilute

H C l

to form compound

C

. The compound

A

when strongly heated gives compound

D

which is used to extract metals.

Metal

X

is:

Q. When metal

XX is treated with sodium hydroxide, a white ppt. of

AA is obtained which is soluble in excess of

NaOHNaOH to form soluble complex

BB.Compound

AA is soluble in dilute

HClHCl to form compound

CC.The compound

AA when strongly heated gives compound

DD which is used to extract metals.

Compound

C

is :

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When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. then metal 'M' is:

The correct option is D AlAl+NaOH→Al(OH)3(white ppt)Al(OH)3+OH−→[Al(OH)4]−solubleAl(OH)3heat−−→Al2O3+3H2O Al2O3 used as adsorbent in column chromatography.Therefore option A is correct

When metal 'M' is treated with $N a O H$ , a white gelatinous precipitate 'X' is obtained, which is soluble in excess of $N a O H$ . Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. then metal 'M' is:

The correct option is D $A l$
$A l + N a O H \to A l (O H)_{3} (w h i t e p p t)$

$A l (O H)_{3} + O H^{-} \to [A l (O H)_{4}]^{-} s o l u b l e$

$A l (O H)_{3} h e a t - - \to A l_{2} O_{3} + 3 H_{2} O$

Al2O3 used as adsorbent in column chromatography.

Therefore option A is correct