When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is:
Al+NaOH→Al(OH)3(whiteppt)
Aluminium hydroxide when reacted with excess sodium hydroxide, the soluble amphoteric compound formed is sodium tetrahydroxoaluminate(III).
Al(OH)3+NaOHexcess→Na[Al(OH)4]soluble
Al(OH)3heat−−→Al2O3+3H2O
Al2O3 used as an adsorbent in column chromatography.
Hence, option A is correct