When metal X reacts with dilute $HCl$ , bubbles of gas Y are formed. Moreover, when this metal X reacts with cold water, it will again produce gas Y. Identify X and Y.

X:- Copper, Y:- Hydrogen

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X:- Potassium, Y:- Oxygen

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X:- Calcium, Y:- Oxygen

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X:- Sodium, Y:- Hydrogen

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Solution

The correct option is D X:- Sodium, Y:- Hydrogen
Metals on reaction with acids, produce metal salts and hydrogen gas except copper, gold etc.

When sodium reacts with dilute $HCl$ it forms sodium chloride and hydrogen gas. The reaction involved is:
$2Na(s) + 2HCl(g) \to {2NaCl(s) + H}_{2} (g)$

Moreover, when it reacts with the cold water it will form sodium hydroxide and hydrogen gas. The hydrogen gas formed immediately catches fire because this reaction generates a lot of heat.

${2Na(s) + H}_{2} O(l) \to {2NaOH(aq) +H}_{2} (g)$

So, X is sodium and Y is hydrogen.

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When metal X reacts with dilute HCl, bubbles of gas Y are formed. Moreover, when this metal X reacts with cold water, it will again produce gas Y. Identify X and Y.

When metal X reacts with dilute $HCl$ , bubbles of gas Y are formed. Moreover, when this metal X reacts with cold water, it will again produce gas Y. Identify X and Y.