When methyl iodide is heated with ammonia, the product obtained is

Methylamine

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Dimethylamine

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Trimethylamine

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All of the above.

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Solution

The correct option is D All of the above.
$C H_{3} I N H_{3} ⟶ C H_{3} N H_{2} C H_{3} I ⟶ (C H_{3})_{2} N H C H_{3} I ⟶ (C H_{3})_{3} N$

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