When $M n O_{2}$ is fused with KOH and $O_{2}$ , what is the product formed and its colour?

MnO - colourless

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K M n O_{4}

- purple

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K_{2} M n O_{4}

- dark green

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M n O_{3}

- black

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Solution

The correct option is B $K_{2} M n O_{4}$ - dark green
In alkaline medium, $H n$ has a stable oxidation state +6. In the presence of $K O H, {M n O}_{2}$ reacts in the presence of atmospheric oxygen to form $K_{2} {M n O}_{4}$ which is a green coloured product.
${2 M n O}_{2} + 4 K O H + O_{2} ⟶ 2 K_{2} {M n O}_{4} + 2 H_{2} O$

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