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Question

When MnO2 is fused with KOH in the presence of KNO3 as an oxidizing agent, it gives a dark green compound (A).
Compound (A) disproportionates in acidic solution to give purple compound (B).
An alkaline solution of compound (B) oxidises KI to compound (C) whereas an acidified solution of compound (B) oxidises KI to (D). Identify (A), (B), (C), and (D).

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Solution

2MnO2+4KOH2K2MnO4(A) Dark Green+2H2O
3MnO24+4H+2MnO4(B) Purple+MnO2+2H2O
In alkaline solution
In this reaction iodine is oxidised to iodate:
2M(B)nO4+H2O+I2MnO2+2OH+I(C)O3
In acidified solutions:
Iodine is liberated from potassium iodide:
10I+2M(B)nO4+16H+2Mn2++8H2O+5(D)I2




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