When moist chlorine reacts with hydrogen sulfide, two products are formed:
A gas which fumes in moist air and, a yellow solid. Name these products.

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Solution

Chlorine gas reacts with hydrogen sulphide $(H_{2} S)$ forming $(HCl)$ and Sulphur.
$HCl$ gas fumes in moist air due to its high solubility So product A must be $HCl$ .
Product B is Sulphur which is a yellow solid.
$\underset{Chlorine gas}{2 {Cl}_{2} (g)} + \underset{Hydrogen Sulphide}{2 H_{2} S (aq)} \to \underset{Hydrogen Chloride}{4 HCl (aq)} + \underset{Sulphur}{2 S (s)}$

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When moist chlorine reacts with hydrogen sulfide, two products are formed: A gas which fumes in moist air and, a yellow solid. Name these products.

Chlorine gas reacts with hydrogen sulphide(H2S) forming (HCl) and Sulphur. HCl gas fumes in moist air due to its high solubility So product A must be HCl.Product B is Sulphur which is a yellow solid.2Cl2(g)Chlorinegas+2H2S(aq)HydrogenSulphide→4HCl(aq)HydrogenChloride+2S(s)Sulphur

When moist chlorine reacts with hydrogen sulfide, two products are formed:
A gas which fumes in moist air and, a yellow solid. Name these products.