When mono brominationn of n-butane occurs at 130- C- the product formed is-

The reaction proceeds via free radical mechanism. As 2^∘ free radical is more stable than 1^∘ free radical, so CH_3CH_2CH(Br)CH_3 would be formed. ...

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Standard XII

Chemistry

Bromination

When mono bro...

Question

When mono brominationn of n-butane occurs at $130^{\circ} C$ , the product formed is:

C H_{3} C H_{2} C H_{2} C H_{2} B r

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Solution

The correct option is B
The reaction proceeds via free radical mechanism.
As $2^{\circ}$ free radical is more stable than $1^{\circ}$ free radical, so $C H_{3} C H_{2} C H (B r) C H_{3}$ would be formed.

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When mono brominationn of n-butane occurs at 130∘C, the product formed is:

The correct option is B The reaction proceeds via free radical mechanism. As 2∘ free radical is more stable than 1∘ free radical, so CH3CH2CH(Br)CH3 would be formed.

When mono brominationn of n-butane occurs at $130^{\circ} C$ , the product formed is:

The correct option is B
The reaction proceeds via free radical mechanism.
As $2^{\circ}$ free radical is more stable than $1^{\circ}$ free radical, so $C H_{3} C H_{2} C H (B r) C H_{3}$ would be formed.