When N is divided by X, the remainder is 28. When N is divided by 10X, the remainder is 125. Find the remainder when N is divided by 5X.
125
Number = Quotient × Divisor + Remainder
Given that:
N = rX+ 28 and N = s*10X+125
⇒ rX+28 = s*10X + 125
Solving the above two equations, we get X(r-10s) = 97.
Therefore X is a factor of 97. So possible values are 1 and 97.
Now X leaves a remainder of 28. Therefore its greater than 28. Thus X=97. 5X=485.
5X will also leave a remainder of 125 (since 5X is a factor of 10X and 5X>125).