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Question

When N is divided by X, the remainder is 28. When N is divided by 10X, the remainder is 125. Find the remainder when N is divided by 5X.


A

100

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B

125

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C

112

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D

none of these

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Solution

The correct option is B

125


Number = Quotient × Divisor + Remainder

Given that:

N = rX+ 28 and N = s*10X+125

rX+28 = s*10X + 125

Solving the above two equations, we get X(r-10s) = 97.

Therefore X is a factor of 97. So possible values are 1 and 97.

Now X leaves a remainder of 28. Therefore its greater than 28. Thus X=97. 5X=485.

5X will also leave a remainder of 125 (since 5X is a factor of 10X and 5X>125).


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