When n resistances each of value R are connected in parallel, then resultant resistance is x. When these n resistances are connected in series, total resistance is

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Solution

The correct option is D

In parallel,

$\frac{1}{R e q}$ = $\frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + . . . . . . + \frac{1}{R_{n}}$

Since all resistances are equal,

$\frac{1}{R e q}$ = $\frac{n}{R}$

$R_{e q}$ = $\frac{R}{n}$

But given this value is equal to x.

Hence x = $\frac{R}{n}$

R = nx

In series, $R_{e q}$ = nR = $n^{2} x$

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\begin{matrix} The resultant resistance of n wires each of resistance r ohms is R, when they are connected in parallel. When these n resistances are connected in series, the resultant resistance will be :- \end{matrix}

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