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Introduction to Oxidation and Reduction

When Na2S2O3 ...

Question

When $N a_{2} S_{2} O_{3}$ reacts with $I_{2}$ to form $N a_{2} S_{4} O_{6}$ and $N a I$ then which statement(s) is correct?

A

n-factor for

N a_{2} S_{2} O_{3}

is one

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B

n-factor for

I_{2}

is two

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C

2 moles of

N a_{2} S_{2} O_{3}

is reacted with 1 mole of

I_{2}

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D

n-factor for

N a_{2} S_{4} O_{6}

is one

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Solution

The correct option is C 2 moles of $N a_{2} S_{2} O_{3}$ is reacted with 1 mole of $I_{2}$
$2 N a_{2} {+ 2 S}_{2} O_{3} + {0 I}_{2} \to N a_{2} {+ 2.5 S}_{4} O_{6} + 2 N a - 1 I$

n-factor of $N a_{2} S_{2} O_{3} = 2 \times (2.5 - 2) = 1$

n-factor of $I_{2} = 2 \times 1 = 2$

n-factor of $N a_{2} S_{4} O_{6} = 4 \times (2.5 - 2) = 2$

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Similar questions

N a_{2} S_{2} O_{3}

I_{2}

N a_{2} S_{4} O_{6}

N a I

then which statement(s) is correct?

N a_{2} S_{2} O_{3}

I_{2}

N a_{2} S_{4} O_{6}

N a I

then which statement(s) is correct?

Q. Identify the oxidant and the reductant in the following reaction respectively:

I_{2} + N a_{2} S_{2} O_{3} \to N a_{2} S_{4} O_{6} + N a I

Balance the following equations:
1. FeCl₃ + NH₄OH → Fe(OH)₃ + NH₄Cl
2. Na₂S₂O₃ + I₂ → Na₂S₄O₆ + NaI

Q. x moles of sulfur get disproportionated in a basic medium and form

N a_{2} S_{2} O_{3}

N a_{2} S

S + N a O H \to N a_{2} S_{2} O_{3} + N a_{2} S

Sodium thiosulfate reacts with iodine in a basic medium to form

N a I

N a_{2} S O_{4}

by the reaction:

N a_{2} S_{2} O_{3} + I_{2} + N a O H \to N a I + N a_{2} S O_{4} + H_{2} O

N a I

is completely precipitated by 2.8 N 100 ml

A g N O_{3}

solution then what is the value of x?

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