Question

When $Na$ reacts with liquid $N{H}_3$ the following substance is formed:

• A. $\left[Na\right(N{H}_3{)}_x{]}^{-}$
• B. $\left[e\right(N{H}_3{)}_y{]}^{-}$
• C. $NaN{H}_2$
• D. $N{a}_{x}N{H}_{3y}$

Answer 1

Answer: (B)

$\left[e\right(N{H}_3{)}_y{]}^{-}$

Sodium (Na) dissolves in liquid ammonia ($N{H}_3$) solution to form a blue colored solution characteristic of a solvated electron in liquid ammonia which is conducting in nature due to presence of solvated electrons.

Reaction is $Na+(x+y)N{H}_3\to \left[Na\right(N{H}_3{)}_x{]}^{+}+\left[e\right(N{H}_3{)}_y{]}^{-}$

So B is correct answer.