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When NaNO3 ...

Question

When $N a N O_{3}$ is treated with $N a$ , we get:

N a_{2} O

and

O_{2}

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N a_{2} O

and

N_{2}

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N a_{2} O_{2}

and

N_{2}

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N a_{2} O

and

N a_{3} N

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Solution

The correct option is B $N a_{2} O$ and $N_{2}$
When $N a N O_{3}$ is treated with sodium, we get $N a_{2} O$ and $N_{2}$ . The reaction is as follows:
$2 N a N O_{3} + 10 N a ⟶ 6 N a_{2} O + N_{2}$
Hence, option B is correct.

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