When $(N H_{4})_{2} C r_{2} O_{7}$ is heated, green coloured residue is:

C r O

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C r_{2} O_{3}

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C r_{2} O_{5}

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C r_{2} O_{7}

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Solution

The correct option is C $C r_{2} O_{3}$
Ammonium di chromate on heating to form chromium oxide and nitrogen gas.
$(N H_{3})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + N_{2} + 4 H_{2} O$
So answer is B.

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Similar questions

(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}

(N H_{4})_{2} C r_{2} O_{7}

C r_{2} O_{3}

(N H_{4})_{2} C r_{2} O_{7} (s) \to C r_{2} O_{3} (s)

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