When nitration of aniline occurs, ortho, meta and para nitro aniline is formed. Arrange them in the increasing order of their $%$ yield.

o > m > p

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m > o > p

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p > o > m

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p > m > o

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Solution

The correct option is D $p > m > o$
Due to +R effect of $- N H_{2}$ , only ortho and para products should be formed. But, in this case due to conversion of $- N H_{2}$ to $- N H_{3}^{+}$ in presence of acidic medium, only –I effect is exerted on benzene ring. Hence, we get the maximum yield of para then meta and minimum yield for ortho product. Therefore, the correct order of yield is $p > m > o$

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When nitration of aniline occurs, ortho, meta and para nitro aniline is formed. Arrange them in the increasing order of their % yield.

When nitration of aniline occurs, ortho, meta and para nitro aniline is formed. Arrange them in the increasing order of their $%$ yield.