When nitrobenzene is treated with $B r_{2}$ in presence of $F e B r_{3}$ the major product formed is m - bromonitrobensene. Statement which is related to obtain the m - isomer is:

The electron density of meta carbon is more than that on ortho and para positions

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Loss of aromaticity when

B r^{+}

attacks at the ortho and para positions and not at meta position

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Easier loss of

H^{+}

to regain aromaticity from the meta position than from ortho and para positions

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None of the above

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Solution

The correct option is A The electron density of meta carbon is more than that on ortho and para positions
The exact influence of a given substituent is seen as its interactions with the delocalized positive charge on the benzonium intermediate generated by bonding to the electrophile at each of the three substitution sites. Nitro groups have a positive charge on the atom bonded to the aromatic ring. Like charges of two groups are destabilized by charge repulsion so meta-products predominate as compared to others.

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Similar questions

Q. Nitrobenzene reacts with

B r_{2}

in the presence of

F e B r_{3}

to give m-bromonitrobenzene as the major product. Which of the following provides the best reason for the formation of m-bromonitrobenzene as the major product?

Q. When nitrobenzene is treated with

B r_{2}

in the presence of

F e B r_{3}

, the major product formed is m-bromonitrobenzene. Choose the statement(s) which is/are related to obtain meta isomer.

Q. Ethyl group

(- C H_{2} C H_{3})

in ethylbenzene increases electron density at which of the following positions?

Assertion (A): - $N O_{2}$ group is benzene ring deactivating and m - directing group

Reason (R): - $N O_{2}$ group with draws electron density from benzene ring and makes ortho and para positions more electron deficient than meta position

Q. Assertion :The para-isomers have higher melting point as compared to their ortho and meta-isomers. Reason: It is due to symmetry of para-isomers that fits in crystal lattice better as compared to ortho- and meta-isomers.

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When nitrobenzene is treated with Br2 in presence of FeBr3 the major product formed is m - bromonitrobensene. Statement which is related to obtain the m - isomer is:

When nitrobenzene is treated with $B r_{2}$ in presence of $F e B r_{3}$ the major product formed is m - bromonitrobensene. Statement which is related to obtain the m - isomer is: