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Question

When non-stoichiometric compound Fe0.95O is heated in the presence of oxygen, it converts into Fe2O3, then which of the following statements are correct?

A
Equivalent weight of Fe0.95O is M0.5 where M is molecular weight of Fe0.95O
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B
The number of moles of Fe3+ and Fe2+ in 1 mole of Fe0.95O are 0.1 and 0.85 respectively
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C
The number of moles of Fe3+ and Fe2+ in 1 moles of Fe0.95O are 0.85 and 0.10 respectively
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D
The % composition of Fe2+ and Fe3+ in the non-stoichiometric compound is 89.47% and 10.53% respectively
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Solution

The correct options are
B The number of moles of Fe3+ and Fe2+ in 1 mole of Fe0.95O are 0.1 and 0.85 respectively
D The % composition of Fe2+ and Fe3+ in the non-stoichiometric compound is 89.47% and 10.53% respectively
Fe0.95O+O2Fe2O3
Let x be the fraction of Fe3+ in the compound then Fe2+=(0.95x)
x×3+(0.95x)×22=0
x=0.1
% of Fe2+=0.850.95×100=89.47%

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