When non-stoichiometric compound Fe0.95O is heated in the presence of oxygen, it converts into Fe2O3, then which of the following statements are correct?
A
Equivalent weight of Fe0.95O is M0.5 where M is molecular weight of Fe0.95O
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B
The number of moles of Fe3+ and Fe2+ in 1mole of Fe0.95O are 0.1 and 0.85 respectively
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C
The number of moles of Fe3+ and Fe2+ in 1moles of Fe0.95O are 0.85 and 0.10 respectively
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D
The % composition of Fe2+ and Fe3+ in the non-stoichiometric compound is 89.47% and 10.53% respectively
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Solution
The correct options are B The number of moles of Fe3+ and Fe2+ in 1mole of Fe0.95O are 0.1 and 0.85 respectively D The % composition of Fe2+ and Fe3+ in the non-stoichiometric compound is 89.47% and 10.53% respectively Fe0.95O+O2→Fe2O3 Let x be the fraction ofFe3+in the compound thenFe2+=(0.95−x) x×3+(0.95−x)×2−2=0 x=0.1 %ofFe2+=0.850.95×100=89.47%