When of the following represent pair of integer (a,b) such that $a \div b = - 3$

(6 + 6, 6 - 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(6 - 2, 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(16 - 4, 4 - 8)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(8, 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(16 - 4, 4 - 8)$
We have to check each option

(A)-

$6 + 6 = 12 6 - 3 = 3$
$\Rightarrow 12 \div 3 = 4$

(B)-

$6 - 2 = 4 1$
$\Rightarrow 4 \div 1 = 4$

(C)-
$16 - 4 = 12 4 - 8 = - 4 \Rightarrow 12 \div - 4 = - 3$

(D)-

$\Rightarrow 8 \div 4 = 2$

Hence, Correct Answer is $C$

Suggest Corrections

Similar questions

(a, b)

a \div b = - 3.

(6, - 2)

6 \div (- 2) = (- 3) .

Write five pairs of integers (a, b) such a ÷ b = − 3. One such pair is (6, − 2) because 6 ÷ (− 2) = (− 3).

\div

\div

Let $3^{a} = 4, 4^{b} = 5, 5^{c} = 6, 6^{d} = 7, 7^{e} = 8$ and $8^{f} = 9$ . What is the value of the product abcdef?

Select the pair of integers $(a, b)$ such that $\frac{a}{b} = - 4$

Join BYJU'S Learning Program