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Standard IX

Chemistry

Atomic Number

When one α ...

Question

When one $α$ and one $β$ particle are emitted by an element, the new element formed will have

Atomic number greater by

1

and mass number greater by

4

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Atomic number less by

1

and mass number less by

4

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Atomic number greater by

1

and mass number less by

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Atomic number less by

1

and mass number greater by

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is C Atomic number less by $1$ and mass number less by $4$
$_{A} X^{m} {- α - - \to}_{A - 2} X^{m - 4} {- β - \to}_{A - 2 + 1} X^{m - 4} =_{A - 1} X^{m - 4}$

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Similar questions

Q. During an

α

-decay, the atomic number of parent element _____________ and mass number ___________ by

4

Q. STATEMENT - 1 :

_{Z} X^{A}

undergoes 2

α

decays, 2

β

decays (negative

β

) and 2 decays. As a result the daughter product is

_{Z - 2} Y^{A - 8} .

STATEMENT -2 : In

α

decay the mass number decreases by 4 unit and atomic number decreases by 2 unit. In

β

decay (negative

β

) the mass number remains unchanged and atomic number increases by 1 unit. In

γ

decay, mass number and atomic number remains unchanged.

Q. An element

X

decays first by positron emission and then 2

α

-particles are emitted in succession. If the product nucleus has mass number

229

and atomic number

89

, then the mass number and atomic number of element

X

are

Q. Assertion :

_{Z} X^{4}

undergoes

2 α - d e c a y s, 2 β - d e c a y s

(negative

β

), and

2 γ - d e c a y s

. As a result, the daughter product is

_{z - 2} Y^{A - B}

Reason: In

α - d e c a y

, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In

β - d e c a y

(negative

β

), the mass number remains unchanged and atomic number increases by 1 unit. In

γ - d e c a y

, mass number and atomic number remain unchanged.

An imaginary radioactive element decays to form elements $X_{1}, X_{2}, X_{3}, X_{4}, X_{5} a n d X_{6}$ , by ejecting two $β$ -particles, followed by an $α$ -particle, and again two ( $β$ -particles followed by an $α$ -particle. What are the mass number and the atomic number of $X_{6}$ ?

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When one α and one β particle are emitted by an element, the new element formed will have

The correct option is C Atomic number less by 1 and mass number less by 4AXm−α−−→A−2Xm−4−β−→A−2+1Xm−4=A−1Xm−4

When one $α$ and one $β$ particle are emitted by an element, the new element formed will have

The correct option is C Atomic number less by $1$ and mass number less by $4$
$_{A} X^{m} {- α - - \to}_{A - 2} X^{m - 4} {- β - \to}_{A - 2 + 1} X^{m - 4} =_{A - 1} X^{m - 4}$