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Question

When one mole of a monoatomic ideal gas at T K undergoes adiabatic change under constant external pressure of 1atm changes from 1L to 2L volume. The final temperature of the gas in Kelvin is

A
T+23×0.0821
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B
T32×0.0821
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C
T(2)23
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D
T
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Solution

The correct option is B T32×0.0821
For Adiabatic process:

TVγ1=constant

T1Vγ11=T2Vγ12

For a monoatomic gas, γ=53
T1V5311=T2V5312
T(1)531=T2(2)531
T2=T2531=T223.


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