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Question

When one mole of an ideal gas is compressed to half of the initial volume and simultaneously heated to twice of its initial temperature, the change in enthalpy (ΔS) is (Considering the process to be isobaric)

A
Cv ln 2
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B
Cp ln 2
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C
R ln 2
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D
(CvR) ln 2
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Solution

The correct option is D (CvR) ln 2
By using the formula,
ΔS=Cvln(T2T1)+R lnV2V1As the gas is heated to twice its temperatureT2=2T1And is compressed to half of its initial volume V2=V12
Substituting the values we get,
ΔS=Cv ln 2+R×ln12=(CvR) ln 2

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