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Question

When one of the slits in Young's experiment is covered with a transparent sheet of thickness 3.6×103 cm the central fringe shifts to a position originally occupied by the 30th brigth fringe. If λ=6000A, the refractive index of the sheet is


A
1.5
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B
1.55
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C

1.60

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D

1.65

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Solution

The correct option is A 1.5

The position of the 30th bright fringe is given by
y30=30λDdHence, the shift of the central fringe is y0=30λDdBut y0=Dd(μ1)t30λDd=Dd(μ1)tor (μ1)=30λt=30×(6000×1010)(3.6×105)=0.5μ=1.5


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