When only carrier is transmitted, antenna current observed is $8 A$ , when it is modulated with $500 H z$ sine wave, antenna current becomes $9.6 A$ . The percentage of modulation is

80 %

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20 %

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93.8 %

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83.76 %

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Solution

The correct option is C $93.8 %$
$\frac{I_{T}}{I_{C}} = \sqrt{(1 + \frac{m^{2}}{2})}$
Hence,
$m^{2} = 2 ({(\frac{I_{T}}{I_{C}})}^{2} - 1) = 2 ({1.2}^{2} - 1) = 0.88$
Hence, $m = \sqrt{0.88} = 93.8 %$

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When only carrier is transmitted, antenna current observed is 8A, when it is modulated with 500 Hz sine wave, antenna current becomes 9.6 A. The percentage of modulation is

The correct option is C 93.8%ITIC=√(1+m22)Hence, m2=2((ITIC)2−1)=2(1.22−1)=0.88Hence, m=√0.88=93.8%

When only carrier is transmitted, antenna current observed is $8 A$ , when it is modulated with $500 H z$ sine wave, antenna current becomes $9.6 A$ . The percentage of modulation is

The correct option is C $93.8 %$
$\frac{I_{T}}{I_{C}} = \sqrt{(1 + \frac{m^{2}}{2})}$
Hence,
$m^{2} = 2 ({(\frac{I_{T}}{I_{C}})}^{2} - 1) = 2 ({1.2}^{2} - 1) = 0.88$
Hence, $m = \sqrt{0.88} = 93.8 %$