When orthoboric acid is strongly heated, residue are :

meta boric acid

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boron

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both

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none of these

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Solution

The correct option is A meta boric acid

Boric acid is soluble in boiling water. When heated above 170 °C, it dehydrates, forming metaboric acid ( $H B O_{2}$ )
$H_{3} B O_{3} \to H B O_{2} + H_{2} O$
Hence option A is correct.

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