When oxalic acid is heated with concentrated $H_{2} S O_{4}$ , it produces:

C O, C O_{2}, H_{2} O

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S O_{2}, C O_{2}, H_{2} O

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C O, O_{3}, H_{2} O

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S O_{2}, S O_{3}, H_{2} O

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Solution

The correct option is A $C O, C O_{2}, H_{2} O$
Sulfuric acid acts as a dehydrating agent.

It removes water from oxalic acid to form carbon monoxide and carbon dioxide.

Option A is correct.

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Similar questions

H_{2} S O_{4}

C u + H_{2} S O_{4} \to C u S O_{4} + {S O}_{2} ↑ + H_{2} O

F e + H_{2} O \to {F e}_{3} O_{4} + H_{2} ↑

{C H}_{4} + O_{2} \to C O_{2} + H_{2} O

Sodium oxalate on heating with conc $H_{2} S O_{4}$ gives

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

C_{6} H_{12} O_{6} + H_{2} S O_{4} \to C O_{2} + S O_{2} + H_{2} O

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