When oxygen gas is passed through Siemens ozoniser,It completely gets converted into ozone gas.The volume of ozone gas produced at STP,if initially 96 g of oxygen gas was taken is
(a) 44.8 L (b) 89.6 L (c) 67.2 L (d) 22.4 L

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Solution

The reaction followed is:
3 O₂ $\overset{electric discharge}{\to}$ 2 O₃
3 moles of oxygen produce 2 moles of ozone.
Or 96 g of oxygen give 96 g of ozone.
Molar mass of ozone = 48 g/mol
1 mole has volume of 22.4 l at STP.
So 2 moles occupies 44.8 l.

Answer is (a).

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When oxygen gas is passed through Siemens ozoniser,It completely gets converted into ozone gas.The volume of ozone gas produced at STP,if initially 96 g of oxygen gas was taken is (a) 44.8 L (b) 89.6 L (c) 67.2 L (d) 22.4 L

The reaction followed is: 3 O2 →electric discharge 2 O3 ​3 moles of oxygen produce 2 moles of ozone. Or 96 g of oxygen give 96 g of ozone. Molar mass of ozone = 48 g/mol ​1 mole has volume of 22.4 l at STP. So 2 moles occupies 44.8 l. Answer is (a).

When oxygen gas is passed through Siemens ozoniser,It completely gets converted into ozone gas.The volume of ozone gas produced at STP,if initially 96 g of oxygen gas was taken is
(a) 44.8 L (b) 89.6 L (c) 67.2 L (d) 22.4 L

The reaction followed is:
3 O₂ $\overset{electric discharge}{\to}$ 2 O₃
3 moles of oxygen produce 2 moles of ozone.
Or 96 g of oxygen give 96 g of ozone.
Molar mass of ozone = 48 g/mol
1 mole has volume of 22.4 l at STP.
So 2 moles occupies 44.8 l.

Answer is (a).