When oxygen is passed through silent electric discharge, it is 10% converted to ozone.
$3 O_{2} (g) ⇌ 2 O_{3} (g)$
What volume of $O_{3}$ will be formed by using 30 litre of $O_{2}$ ?

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Solution

we have,
22.4 L of gas = 1 mole
30 L of gas = $\frac{30}{22.4}$ = 1.33 mole

according to equation, we have

3 mole of $O_{2}$ is producing 2 moles of $O_{3}$

so, 1.33 moles of $O_{2}$ produce $O_{3}$ = $\frac{2}{3} * 1.33$ = 0.886 mole

and only 10% is converted to $O_{3}$
therefore the amount of $O_{3}$ produced = 0.886 * 0.1 = 0.0886 mole
volume of $O_{3}$ produced = 0.0886 * 22.4 L = 1.984 L

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When oxygen is passed through silent electric discharge, it is 10% converted to ozone. 3O2(g)⇌2O3(g)What volume of O3 will be formed by using 30 litre of O2 ?

When oxygen is passed through silent electric discharge, it is 10% converted to ozone.
$3 O_{2} (g) ⇌ 2 O_{3} (g)$
What volume of $O_{3}$ will be formed by using 30 litre of $O_{2}$ ?