When $P H_{3}$ absorbed in $H g C l_{2}$ solution the corresponding phosphide is obtained

H g_{2} P_{3}

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H g_{3} P_{2}

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H g_{3} (P O_{4})_{2}

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None of these

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Solution

The correct option is B $H g_{3} P_{2}$
$2 P H_{3} + 3 H g C l_{2} \to H g_{3} P_{2} + 6 H C l$

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