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Emission and Absorption Spectra

When photon o...

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When photon of energy 4.25eV strikes the surface of metal A the ejected photoelectrons have a maximum kinetic energy,Ta and de broglie wavelength A. The maximum kinetic energy of photoelectrons liberated from another metalB by photon of energy 4.70 eV is Tb =Ta-1.50eV. If the de broglie wavelength of these photoelectrons is waveleght of B =2 wavelength of A then which is not correct (A) the work function of A is 2.25ev (B) the work function of B is 1.20 ev (C) Ta=2.00ev (D) Tb= 0.5 ev

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Q. When photons of energy 4.25 eV strike the surface of metal A, the ejected photoelectrons have maximum kinetic energy

T_{A}

and de Broglie wavelength

λ_{A}

. The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 eV is

T_{B} = (T_{A} - 1.50) e V

. If the de Broglie wavelength of these photoelectrons is

λ_{B} = 2 λ_{A}

Q. When photon of energy

4.0 eV

strikes the surface of a metal

A

, the ejected photoelectrons have maximum kinetic energy

T_{A} eV

and de- Broglie wavelength

λ_{A}

. The maximum kinetic energy of photoelectrons liberated from another metal

B

by a photon of energy

4.50 eV

T_{B} = (T_{A} - 1.5) eV

. If the de-Broglie wavelength of these photo electrons

λ_{B} = 2 λ_{A}

, then the work function of metal

B

Q. When photons of energy 4.25 eV strike the surface of metal A, the ejected photoelectrons have maximum kinetic energy

T_{A}

and de Broglie wavelength

λ_{A} .

The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 eV is

T_{B} = (T_{A} - 1.50) e V .

If the de Broglie wavelength of these photoelectrons is

λ_{B} = 2 λ_{A},

Q. When photoelectrons of energy

4.25 e V

strike the surface of metal

A

, the ejected photoelectrons have maximum kinetic energy

T_{A} e V

and de-Broglie wavelength

λ_{A}

. The maximum kinetic energy of photoelectrons liberated from another metal

B

by photons of energy

4.70 e V

T_{B} = (T_{A} - 1.5) e V

. If de-Broglie wavelength of these photoelectrons is

λ_{B} = 2 λ_{A}

Q. When protons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy

T_{A}

expressed in eV and de-Broglie wavelength

λ_{A}

. The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 eV is

T_{B}

T_{A}

– 1.50 eV). If the de-Broglie wavelength of these photoelectrons is

λ_{B} = 2 λ_{A}

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