When photons of energy 4-25 eV strike the surface of metal A- the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength -A- The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4-70 eV is TB - TA - 1-5 eV- If de-Broglie wavelength of these photoelectrons is -B - 2-A- then

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When photons ...

Question

When photons of energy $4.25 eV$ strike the surface of metal $A$ , the ejected photoelectrons have maximum kinetic energy $T_{A} eV$ and de-Broglie wavelength $λ_{A}$ . The maximum kinetic energy of photoelectrons liberated from another metal $B$ by photons of energy $4.70 eV$ is $T_{B} = (T_{A} - 1.5) eV$ . If de-Broglie wavelength of these photoelectrons is $λ_{B} = 2 λ_{A}$ , then

T_{A} = 2.00 eV

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Work function of

B

4.20 eV

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Work function of

A

2.25 eV

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T_{B} = 2.75 eV

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Solution

The correct option is C Work function of $A$ is $2.25 eV$
Apply Einstein photoelectric equation

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Similar questions

Q. When photons of energy 4.25 eV strike the surface of metal A, the ejected photoelectrons have maximum kinetic energy

T_{A}

and de Broglie wavelength

λ_{A}

. The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 eV is

T_{B} = (T_{A} - 1.50) e V

. If the de Broglie wavelength of these photoelectrons is

λ_{B} = 2 λ_{A}

, then :

Q. When photons of energy 4.25 eV strike the surface of a metal

A

. The ejected photoelectrons have a maximum kinetic energy

T_{(A)}

(expressed in eV) and de-Broglie wavelength

λ_{(A)}

. The maximum kinetic energy of photoelectrons liberated from another metal

B

by photons of energy 4.2 eV is

T_{B}

. Where

T_{B} = (T_{A} - 1.5)

. If the de-Broglie wavelength of these photoelectrons is

λ_{B}

, where,

(λ_{B} = 2 λ_{A})

, then which of the following is not correct?

Q. When photon of energy

4.0 eV

strikes the surface of a metal

A

, the ejected photoelectrons have maximum kinetic energy

T_{A} eV

and de- Broglie wavelength

λ_{A}

. The maximum kinetic energy of photoelectrons liberated from another metal

B

by a photon of energy

4.50 eV

T_{B} = (T_{A} - 1.5) eV

. If the de-Broglie wavelength of these photo electrons

λ_{B} = 2 λ_{A}

, then the work function of metal

B

is:

Q. When photoelectrons of energy

4.25 e V

strike the surface of metal

A

, the ejected photoelectrons have maximum kinetic energy

T_{A} e V

and de-Broglie wavelength

λ_{A}

. The maximum kinetic energy of photoelectrons liberated from another metal

B

by photons of energy

4.70 e V

T_{B} = (T_{A} - 1.5) e V

. If de-Broglie wavelength of these photoelectrons is

λ_{B} = 2 λ_{A}

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Q. When photons of energy

4.25 e V

strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy of

K_{A}

eV and de Broglie wavelength

λ_{A}

. The maximum kinetic energy of photo electrons liberated from another metal B by photons of energy

4.70 e V

K_{B} = (K_{A} - 1.5) e V

. If the de Broglie wavelength of these photoelectrons is

λ_{B} = 2 λ_{A}

then

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The correct option is C Work function of A is 2.25 eVApply Einstein photoelectric equation

The correct option is C Work function of $A$ is $2.25 eV$
Apply Einstein photoelectric equation