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Question

# When photons of wavelength λ1 are incident on a metal plate, the corresponding stopping potential is found to be V. When photons of wavelength λ2 are used, the corresponding stopping potential was thrice the above value. If light of wavelength λ3 is used, the stopping potential for wavelength λ3 in terms of λ1 and λ2 will be

A
hce(1λ3+12λ21λ1]
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B
hce(1λ3+12λ232λ1]
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C
hce(1λ3+1λ21λ1]
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D
hce(1λ31λ21λ1]
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Solution

## The correct option is B hce(1λ3+12λ2−32λ1]KEλ1=hcλ1−ψ=eΔV KEλ2=hcλ2−ψ=3eΔV ⇒ 3(hcλ1−ψ) = hcλ2−ψ⇒ψ = hc(32λ1−12λ2) ⇒KEλ3=hcλ3−hc(32λ1−12λ2]=hc[1λ3+12λ2−32λ1] eΔV = hc(1λ3+12λ2−32λ1]ΔV= hce(1λ3+12λ2−32λ1]

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