When potassium ferrocyanide crystals are heated with conc. $H_{2} {S O}_{4}$ , the gas evolved is:

{S O}_{2}

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{N H}_{3}

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{C O}_{2}

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C O

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Solution

The correct option is C $C O$
When potassium ferrocyanide crystals are heated with conc. $H_{2} {S O}_{4}$ , the gas evolved is $C O$ .

$K_{4} [{F e (C N)}_{6}] + 6 H_{2} {S O}_{4} + 6 H_{2} O ⟶ 2 K_{2} {S O}_{4} + F e {S O}_{4} + 3 {({N H}_{4})}_{2} {S O}_{4} + 6 C O ↑$

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