When potassium hydrogen sulphate is attacked by fluorine,the product formed is:

K_{2} S O_{4}

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K_{2} S_{2} O_{4}

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K_{2} S_{2} O_{7}

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K_{2} S_{2} O_{8}

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Solution

The correct option is D $K_{2} S_{2} O_{8}$
$2 K M n S O_{4} F \to K_{2} S_{2} O_{8}$
$K M n S O_{4}$ is attacked by Florine, $K_{2} S_{2} O_{8}$ is formed

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