Question

when pressure is increased by 2%, what is the percentage decrease in the volume of a gas, if boyles law is obeyed

Answer 1

Dear Student ,
Look ,here in this case ,
$$\begin{gathered} \frac{P_1}{P_2}=\frac{V_2}{V_1} \\ \Rightarrow \frac{100}{102}=\frac{V_2}{V_1} \\ \Rightarrow \frac{V_2-V_1}{V_1}=\frac{100-102}{102} \\ Therefore,\frac{∆V}{V}=\frac{-2}{100}\times \frac{∆V}{V}=2\% \end{gathered}$$

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