When processing flower nector into honeybees extract, a considerable amount of water gets reduced. How much flower-nector must be processed to yield $1$ kg of honey, if nector contains $50 %$ water and the honey obtained from this nector contains $15 %$ water.

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Solution

Flower- nector contains $50 %$ of non-water part.
In honey, this non-water part constitutes $85 % (100 - 15)$ .
Therefore, $0.5 \times$ Amount of flower-nector $= 0.85 \times$ Amount of honey $= 0.85 \times 1$ kg.
Therefore, amount of flower-nector needed $= (\frac{0.85}{0.5} \times 1)$ kg $= 1.7$ kgs.

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When processing flower nector into honeybees extract, a considerable amount of water gets reduced. How much flower-nector must be processed to yield 1 kg of honey, if nector contains 50% water and the honey obtained from this nector contains 15% water.

Flower- nector contains 50% of non-water part.In honey, this non-water part constitutes 85%(100−15). Therefore, 0.5× Amount of flower-nector =0.85× Amount of honey =0.85×1 kg.Therefore, amount of flower-nector needed =(0.850.5×1) kg =1.7 kgs.

When processing flower nector into honeybees extract, a considerable amount of water gets reduced. How much flower-nector must be processed to yield $1$ kg of honey, if nector contains $50 %$ water and the honey obtained from this nector contains $15 %$ water.