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Question

When propanamide reacts with Br2 and NaOH then which of the following compound is formed

A

Ethyl alcohol

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B

Propyl alcohol

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C
Propyl amine
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D
Ethylamine
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Solution

The correct option is D Ethylamine
CH3CH2CONH2Br2/KOH−−−−−−−−−−−−−−−−−−Hofmann bromarride reactionCH3CH2NH2Ethylamine

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