When q(x)=2x3−5x2+3x+7 is divided by x+2, then the remainder is R1. The value of R21 is
A
−1225
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B
−35
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C
1225
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D
35
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Solution
The correct option is C1225 q(x)=2x3−5x2+3x+7 x+2=0⇒x=−2
By remainder theorem, R1=2(−2)3−5(−2)2+3(−2)+7 =−16−20−6+7 R1=−35 R21=(−35)2=1225
So, the correct answer is option (c).