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Byju's Answer
Standard VII
Mathematics
Sum / Principal
When required...
Question
When required the following logarithms may be used.
log
2
=
.3010300
,
log
3
=
.4771213
,
log
7
=
.8450980
,
log
11
=
1.0413927
.
Show that money will increase more than a hundredfold in a century at
5
per cent. compound interest.
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Solution
Let
P
be the Principal in pound.
R
be the interest rate .
n
be the number of year.
S
.
I
be the simple interest.
D
be the discount .
M
be amount
M
=
P
(
1
+
R
100
)
n
S
.
I
=
P
×
R
×
n
D
=
P
×
R
×
n
1
+
R
n
Thus,
M
=
P
(
1
+
5
100
)
100
M
=
P
(
21
20
)
100
Taking
log
both side .
log
M
=
log
P
+
100
(
log
21
)
−
100
(
log
20
)
log
M
=
log
P
+
2.11898
M
=
P
×
10
2.11898
Thus
M
is greater than
P
×
100
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0
Similar questions
Q.
When required the following logarithms may be used.
log
2
=
.3010300
,
log
3
=
.4771213
,
log
7
=
.8450980
,
log
11
=
1.0413927
.
In how many years will a sum of money double itself at
5
per cent. compound interest?
Q.
When required the following logarithms may be used.
log
2
=
.3010300
,
log
3
=
.4771213
,
log
7
=
.8450980
,
log
11
=
1.0413927
.
In how many years will
1000
pounds become
2500
pounds at
10
per cent. compound interest?
Q.
When required the following logarithms may be used.
log
2
=
.3010300
,
log
3
=
.4771213
,
log
7
=
.8450980
,
log
11
=
1.0413927
.
What sum of money at
6
per cent. compound interest will amount to
1000
pounds in
12
years? Given
log
106
=
2.0253059
,
log
49697
=
4.6963292
.
Q.
When required the following logarithms may be used.
log
2
=
.3010300
,
log
3
=
.4771213
,
log
7
=
.8450980
,
log
11
=
1.0413927
.
Find the amount of
100
pounds in
50
years, at
5
per cent. compound interest; given
log
114.674
=
2.0594650
.
Q.
When required the following logarithms may be used.
log
2
=
.3010300
,
log
3
=
.4771213
,
log
7
=
.8450980
,
log
11
=
1.0413927
.
What is the amount of a farthing in
200
years at
6
per cent. compound interest? Given
log
106
=
2.0253059
,
log
115.0270
=
2.0611800
.
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