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Non-Ideal Battery

When resistan...

Question

When resistance of 30 $Ω$ is connected to a battery, the current in the circuit is 0.4 A. if this resistance is replaced by 10 $Ω$ resistance, the current is 0.8 A. Then e.m.f. and the internal resistance of thebattery are

A

10 V, 16 Ω

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B

3 V, 20 Ω

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C

16 V, 10 Ω

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D

24 V, 32 Ω

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Solution

The correct option is C $16 V, 10 Ω$
$E = I_{1} [R_{1} + r] = I_{2} [R_{2} + r] 0.4 [30 + r] = 0.8 [10 + r] 30 + r = 20 + 2 r r = 10 E = 0.4 [30 + 10] E = 16 V$

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