Question

When silver nitrate solution is added to potassium iodide solution then the sol produced is :

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Answer 1

When silver nitrate is added to excess $KI$, $AgI$ gets precipitated.
$AgN{O}_3\left(aq\right)+KI\left(aq\right)\to AgI\left(s\right)\downarrow +AgN{O}_3\left(aq\right)$

The precipitated silver iodide adsorbs iodide ions $\left(I^{-}\right)$ from the dispersion medium and negatively charged colloidal sol is formed $AgI/I^{-}$.


Hence, option (d) is correct.