When Sn reacts with calculated amount of $H g C l_{2}$ and excess $H g C l_{2}$ , then the product will be respectively.

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Solution

The correct option is A

This is one of the cases in chemistry where you will see that the amount of reactant is very important to get the product.
When Sn is heated with calculated amount of $H g C l_{2}$ , anhydrous $S n C l_{2}$ is formed.
$S n + H g C l_{2} \to S n C l_{2} + H g$
and, by heating Sn with excess of $H g C l_{2}$ , Stannic Chloride is formed.

$S n + 2 H g C l_{2} \to S n C l_{4} + 2 H g$

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Similar questions

H g C l_{2} + S n C l_{2} \to 2 H g + S n C l_{4}

Valency of tin in $S n C l_{2}$ and $S n C l_{4}$ is _______ and _______ respectively.

H g C l_{2}, S n C l_{2}

F_{2} O

S n C l_{2}

H g C l_{2}

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