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Question

whenSO2 is passed in a solution of potassium iodate, the oxidation state of iodine changes from :


A

+5 to 0

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B

+5 to -1

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C

-5 to 0

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D

-7 to -1

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Solution

The correct option is A

+5 to 0


When SO2 gas is passed into a solution of KIO3, the products are I2, H2SO4 and K2SO4.
The balanced equation for the reaction is:

5+4S2O2+4+1H22O+2+1K+5I2O3+1K2+6S2O4+0I2++1H2+6S2O4

As you can see, the I in the IO3 has a +5 oxidation state, which is changed to 0 in I2


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